2x^2-25x+256=0

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Solution for 2x^2-25x+256=0 equation:


Simplifying
2x2 + -25x + 256 = 0

Reorder the terms:
256 + -25x + 2x2 = 0

Solving
256 + -25x + 2x2 = 0

Solving for variable 'x'.

Begin completing the square.  Divide all terms by
2 the coefficient of the squared term: 

Divide each side by '2'.
128 + -12.5x + x2 = 0

Move the constant term to the right:

Add '-128' to each side of the equation.
128 + -12.5x + -128 + x2 = 0 + -128

Reorder the terms:
128 + -128 + -12.5x + x2 = 0 + -128

Combine like terms: 128 + -128 = 0
0 + -12.5x + x2 = 0 + -128
-12.5x + x2 = 0 + -128

Combine like terms: 0 + -128 = -128
-12.5x + x2 = -128

The x term is -12.5x.  Take half its coefficient (-6.25).
Square it (39.0625) and add it to both sides.

Add '39.0625' to each side of the equation.
-12.5x + 39.0625 + x2 = -128 + 39.0625

Reorder the terms:
39.0625 + -12.5x + x2 = -128 + 39.0625

Combine like terms: -128 + 39.0625 = -88.9375
39.0625 + -12.5x + x2 = -88.9375

Factor a perfect square on the left side:
(x + -6.25)(x + -6.25) = -88.9375

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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